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2x^2+21x-7.3=0
a = 2; b = 21; c = -7.3;
Δ = b2-4ac
Δ = 212-4·2·(-7.3)
Δ = 499.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{499.4}}{2*2}=\frac{-21-\sqrt{499.4}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{499.4}}{2*2}=\frac{-21+\sqrt{499.4}}{4} $
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